connect to sugarcrm and get some data in my custom php file

plus print current_user it come up wd details of logged in user.
whats wrong with $name = $current_user->name; ?

So I think now using this $db you can perform any mysql operations.

For current user I have checked that,

you have to pass current user id as a POST variable to access in ajax file and get all info using retrieve function.

Hi Umar and Devang,

I dont find 'name' field in users table.

Can you try check with $current_user->first_name?

Thanks!.

Hi Ajay

current_user is not accessible in this case.

For current user I have checked that,

You have to pass current user id as a POST variable to access in ajax file and get all info using retrieve function.

Try with this,

<?php

if(!defined('sugarEntry'))

  define('sugarEntry', true);

ini_set("display_errors", 1);

require_once ('include/entryPoint.php');

global $db, $current_user;

$userId = $_REQUEST['userId'];

if(empty($current_user->id)){

  $current_user->retrieve($userId);

}

Devang any solution buddy?

Yes Umar, As I have posted  you can pass current user id as a post variable while making ajax call.

And apply following code in your sample.php file.

<?php

if(!defined('sugarEntry'))

  define('sugarEntry', true);

require_once ('include/entryPoint.php');

global $db, $current_user;

$userId = $_REQUEST['userId'];

if(empty($current_user->id)){

  $current_user->retrieve($userId);

}

$name = $current_user->name;

echo $name;

?>

Hello Devang,
With your logic i am able to access properties of logged in user. Thank You so much
Now kindly please tell me how to do query in my sample_info.php page ?

Hello Devang,

Buddy i have done that query thing used the $db variable ..Thankyou so much once again